4^2x+7=32^4x-1

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Solution for 4^2x+7=32^4x-1 equation: 



4^2x+7=32^4x-1

We move all terms to the left:

4^2x+7-(32^4x-1)=0

We get rid of parentheses

4^2x-32^4x+1+7=0

We add all the numbers together, and all the variables

4^2x-32^4x+8=0

We move all terms containing x to the left, all other terms to the right

4^2x-32^4x=-8

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